0.3x^2+20x+3300=0.01x^2+x+5

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Solution for 0.3x^2+20x+3300=0.01x^2+x+5 equation: 



0.3x^2+20x+3300=0.01x^2+x+5

We move all terms to the left:

0.3x^2+20x+3300-(0.01x^2+x+5)=0

We get rid of parentheses

0.3x^2-0.01x^2+20x-x-5+3300=0

We add all the numbers together, and all the variables

0.29x^2+19x+3295=0

a = 0.29; b = 19; c = +3295;
Δ = b2-4ac
Δ = 192-4·0.29·3295
Δ = -3461.2
Delta is less than zero, so there is no solution for the equation

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